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I want to search for two tags simultaneously using the /questions/tagged/<tag list> search method, and allow one tag to be a wildcard. Is this possible?

For example when searching for Actionscript mocking questions with the query http://stackoverflow.com/questions/tagged/actionscript%20mock* seems to be resolved, per the page <title> and sidebar as:

Highest Voted 'actionscript mocking or mockito or mockups or mockup-tool or mocking-framework or mockrunner or mockolate or mockrepository or mockme or mockjax or mockery' Questions - Stack Overflow

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which returns loads of irrelevant results.

Presumably the wildcard is being expanded before building the predicate tree which is resulting in this unexpected behaviour.

Are there any ways to get around this behaviour at present?

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Reproduced in Chrome 14 on Windows XP on SO, MSO, and SE 2.0. –  Kevin Vermeer Oct 20 '11 at 12:19
    
Seems related to this post on theoretical CS, but I can't find the implementation details on MSO. –  Kevin Vermeer Oct 20 '11 at 15:41
    
I've pinged Sam about this on that theoretical CS post, he should respond here (or he'll reply to me and I'll respond here) with more information. –  Kevin Vermeer Oct 20 '11 at 19:47
    
having a think about this, we can change the precedence of the tag expantion @KevinVermeer –  waffles Oct 21 '11 at 4:41
    
Thanks for all your investigation and input @Kevin! –  yjo Oct 21 '11 at 14:02

1 Answer 1

Searching for [actionscript] mock* seems to return any question with having the mock* as the search condition

http://stackoverflow.com/search?q=%5Bactionscript%5D+mock*

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This is what I thought at first until I read more carefully. This answer is unrelated to the question; you're using /search?q=<tag list> and the question is about wildcard and logical operator functionality in /questions/tagged/<tag list>. –  Kevin Vermeer Oct 20 '11 at 15:29
    
For example, /questions/tagged/embedded c arm returns a list of questions tagged with [embedded] AND [c] AND [arm]. I'm not sure how to invoke the OR operator. –  Kevin Vermeer Oct 20 '11 at 15:34

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