Meta Stack Exchange is where users like you discuss bugs, features, and support issues that affect the software powering all 157 Stack Exchange communities.

What is meta?
Here's how it works:
  1. Any Stack Exchange user can ask a question
  2. The community provides support, votes on ideas, and reports bugs
  3. Your voice helps shape the way Stack Exchange operates

The new deletion rules say:

popular questions require more deletion votes to be deleted, at a ratio of 20:1 - a question's popularity is defined by the sum of its score plus all its answers' scores.

Is there an easy way to determine a questions "score", or alternatively to determine how many delete votes would be required to close that question? For example, 1764090 is up to 11 votes; I have no idea if it needs 1 more vote or 30. I could find out by voting to delete, but obviously that's less than ideal

If there is no other way, it might be useful to include that information somewhere; for example, changing the link to say "delete (11/12)"

share|improve this question
up vote 11 down vote accepted

As of 14th March, 2013:

A question (or answer) with Votes to Close (or Delete) now shows the number of votes already cast and the number of votes needed to close (or delete) (e.g., (2/5))

For example:

http://stackoverflow.com/q/632808/1190388

share|improve this answer

If you hover (11) in delete (11), it will show you 14 more votes needed to delete.

share|improve this answer
1  
Ah, of course. Every time I can't find information on SO it turns out to be in a tooltip. Thanks – Michael Mrozek Jun 26 '10 at 9:31
    
On an unrelated note, what did you use to add the timeline link? I assumed it was a greasemonkey script, but I can't find it and remain too lazy to write it myself – Michael Mrozek Jun 26 '10 at 18:15
2  
@Michael, yeah it is a greasemonkey script. – YOU Jun 26 '10 at 18:30
    
@S Great, thanks – Michael Mrozek Jun 26 '10 at 18:52

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .