# What's the next awesome number after π? [closed]

Today, I was foolish enough to use the rollback button. Now on stack overflow I no longer have 3 silver badges and 14 bronze badges. My joy in opening the website every day in a pinned tab in Chrome is severely diminished now. FML

I know that badges once given can't be taken away. What's the next awesome number I should aim for, then?

I could get 3 gold badges and 11 silver badges, which would get me •3 •14 •15 -- but that's nearly impossible to do without getting more bronze badges.

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## closed as off-topic by animuson, hims056, Azik, Martijn Pieters, Aziz ShaikhApr 29 at 7:33

This question appears to be off-topic. The users who voted to close gave this specific reason:

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•6 •66 could be doable... –  badp Jun 30 '10 at 12:41
Be rational, get real. –  BalusC Jun 30 '10 at 13:09
@Balus: You mean •22 •7? :/ –  badp Jun 30 '10 at 13:12
a c-ish answer would be: pi++; –  akira Jun 30 '10 at 13:26
–  Kip Jun 30 '10 at 13:37
It's NOT Friday. –  rlb.usa Jun 30 '10 at 17:21
@kip: We have a mathoverflow?! –  TheLQ Jun 30 '10 at 18:05

 Symbol | Value                                         | Name
--------+-----------------------------------------------+---------------------------------------
0      | = 0                                           | Zero
1      | = 1                                           | One, Unity
i      | = \sqrt{-1}                                   | Imaginary unit
π      | ≈ 3.14159 26535 89793 23846 26433 83279 50288 | Pi, Archimedes' constant
e      | ≈ 2.71828 18284 59045 23536 02874 71352 66249 | Napier's constant, or Euler's number
√2     | ≈ 1.41421 35623 73095 04880 16887 24209 69807 | Pythagoras' constant, square root of 2
√3     | ≈ 1.73205 08075 68877 29352 74463 41505 87236 | Theodorus' constant, square root of 3
√5     | ≈ 2.23606 79774 99789 69640 91736 68731 27623 | square root of 5
γ      | ≈ 0.57721 56649 01532 86060 65120 90082 40243 | Euler-Mascheroni constant
φ      | ≈ 1.61803 39887 49894 84820 45868 34365 63811 | Golden ratio
ρ      | ≈ 1.32471 79572 44746 02596 09088 54478 09734 | Plastic constant
β*     | ≈ 0.70258                                     | Embree-Trefethen constant
δ      | ≈ 4.66920 16091 02990 67185 32038 20466 20161 | Feigenbaum constant
α      | ≈ 2.50290 78750 95892 82228 39028 73218 21578 | Feigenbaum constant
C2     | ≈ 0.66016 18158 46869 57392 78121 10014 55577 | Twin prime constant
M1     | ≈ 0.26149 72128 47642 78375 54268 38608 69585 | Meissel-Mertens constant
B2     | ≈ 1.90216 05823                               | Brun's constant for twin primes
B4     | ≈ 0.87058 83800                               | Brun's constant for prime quadruplets
Λ      | ≥ –2.7 • 10−9                                 | de Bruijn-Newman constant
K      | ≈ 0.91596 55941 77219 01505 46035 14932 38411 | Catalan's constant
K      | ≈ 0.76422 36535 89220 66299 06987 31250 09232 | Landau-Ramanujan constant
K      | ≈ 1.13198 824                                 | Viswanath's constant
B´L    | = 1                                           | Legendre's constant
μ      | ≈ 1.45136 92348 83381 05028 39684 85892 02744 | Ramanujan-Soldner constant
EB     | ≈ 1.60669 51524 15291 76378 33015 23190 92458 | Erdős–Borwein constant
β      | ≈ 0.28016 94990 23869 13303                   | Bernstein's constant
λ      | ≈ 0.30366 30028 98732 65859 74481 21901 55623 | Gauss-Kuzmin-Wirsing constant
σ      | ≈ 0.35323 63718 54995 98454                   | Hafner-Sarnak-McCurley constant
λ,μ    | ≈ 0.62432 99885 43550 87099 29363 83100 83724 | Golomb–Dickman constant
Λ      | ≈ 1.09868 58055                               | Lengyel's constant
ζ(3)   | ≈ 1.20205 69031 59594 28539 97381 61511 44999 | Apéry's constant
θ      | ≈ 1.30637 78838 63080 69046 86144 92602 60571 | Mills' constant
K      | ≈ 2.58498 17595 79253 21706 58935 87383 17116 | Sierpiński's constant
F      | ≈ 2.80777 02420 28519 36522 15011 86557 77293 | Fransén-Robinson constant
L      | ≈ 0.5                                         | Landau's constant
P2     | ≈ 2.29558 71493 92638 07403 42980 49189 49039 | Parabolic constant
Ω      | ≈ 0.56714 32904 09783 87299 99686 62210 35555 | Omega constant


Personally I don't care about special numbers like pi, but what would have been cool is to have the badge numbers to be exactly the same as the reputation points. So for example, if I had a reputation of 12345, then I'd like at the moment have 1 gold, 23 silver and 45 bronze (and quickly take a screen).

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How would you do it with 2207 rep? –  mmyers Jun 30 '10 at 14:51
@mmyers: Who says that it stays 2207 all the time? Make it thrilling! –  BalusC Jun 30 '10 at 15:00
On StackOverflow he needs •6 •47 •60 and has •4 •36 •67 so he's close enough... –  badp Jun 30 '10 at 16:08
Or get one more gold at meta and gain 2315 rep :P The question is, which gold is easy to earn after fanatic? Electorate? –  BalusC Jun 30 '10 at 16:50
Technically, Electorate is the generally easiest gold to acquire of them all (least amount of days, and no luck involved). –  Grace Note Jun 30 '10 at 17:15

Obviously, the most awesome course of action would be to get a badge count of i. I don't know how you will accomplish this, but I guarantee you that once you do, you'll be the envy of everyone.

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A 1 looks a bit like an i –  Charles Stewart Jun 30 '10 at 13:49
@Charles, so then it's just a job of picking the right browser font. –  Lance Roberts Jun 30 '10 at 15:09

Well e is less than π, so that wouldn't work. What about Avogadro's constant, 6.02e23:

•6 •02 •23

Except it wouldn't display the silver badges with the leading zero of course

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Then you should strive to get 602 silver and 23 bronze. –  Grace Note Jun 30 '10 at 13:38
I somehow missed your answer... –  perbert Jun 30 '10 at 14:01
60 silver and 223 bronze is possible, but you'll be hard-pressed to keep from getting at least one gold. –  mmyers Jul 2 '10 at 19:34

Goal: •31 •415 •9265

Get cracking. You'll never achieve that by messing about on MSO.

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Sadly, Jon Skeet can't ever do this because he already has 696 silver badges. –  mmyers Jun 30 '10 at 14:06
This looks like a joke...except that Jon Skeet has actually exceeded both of the scores for both Gold and Silver. The Bronze, however, he is nowhere near. He would have to post a lot more consistently mediocre answers to achieve this. –  beska Jun 30 '10 at 14:07
I Simulskeeted. –  beska Jun 30 '10 at 14:07
926 bronzes is more realistic. –  BalusC Jun 30 '10 at 14:21

I think your best option would be to go to area51 and get behind the mathematics proposal. You can then try to accomplish the same thing there :-)

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If this is something that you are severely and completely distressed about (despondent, even), you could email team@stackoverflow.com, and request that they obliterate whichever badge it is that offends you so.

Of course, they're quite busy, so this would be ridiculous. But the option is still there.

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That would be cheating! –  badp Jun 30 '10 at 12:40
Not if there was an "annoying the SO team about dumb stuff" ANTI badge. –  detly Jun 30 '10 at 13:03

•13 •37 Perhaps? If you like that sort of thing.

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•4 •20

I know nothing, I swear.

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Possibly the wrong audience for this answer. lol –  Jon Seigel Jun 30 '10 at 13:46
you don't think people at the site with the rainbow pony avatars know anything about marih juh wanna? –  Kip Jun 30 '10 at 20:45

# e

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A.K.A. 2.71828182845904523536… and lim n→∞ (1+1/n)^n –  perbert Jun 30 '10 at 13:57
Of course, you'd have to get •27 •18 •28... –  perbert Jun 30 '10 at 13:59
•2 •71 •82 or even •2 •71 •828 might be a little more likely. –  Tom Hawtin - tackline Jun 30 '10 at 14:02
For some reason I misread and thought that he already had 3 golden badges, but yea, you are right. –  perbert Jun 30 '10 at 15:51

I once hoped I could get my user ID number: •5 •27 •38

But alas, I got one too many bronze badges on SO. And I only needed one more gold and 5 more silvers to do it. Woe is me.

You could still do it though: •1 •39 •92

Get crackin' on some moderately good answers!

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