Possible Duplicate:
Simple way to report spammy users?

A question i asked got a reply from a spam user account.


what's the best way to report these findings?


Flag the answer as spam.

Step one:

     Click the "flag" link below the offending answer

Step two:

     Select the "it is spam" flag reason, then click the "Flag Answer" button

Step three:

     There is no step three.

Note that if you happen across an account that has posted multiple spam answers, it's not necessary to painstakingly flag each of their answers as spam. Rather, flag one of their answers, then select the "other" option under "it needs moderator attention" and explain in the textbox provided what the problem is. The moderator who processes your flag will blow away the entire account, taking all of the the offending answers with it.

  • 2
    My instinct made me try to downvote the screenshot after reading it. :P Apr 12 '12 at 6:12
  • I know how to flag a -post- .. i ment to flag a -USER-
    – Pure.Krome
    Apr 12 '12 at 6:17
  • 4
    @Pure: You can't flag a user. You can, however, flag a post made by a user.
    – Cody Gray
    Apr 12 '12 at 6:18
  • 1
    I disagree with the flag. A Mod-flag explaining that the whole account can be purged might be better suited...if the name of the account is not a dead give-away, that is... Apr 12 '12 at 6:32
  • 2
    @Bobby Yes, a mod flag would be equally helpful. No, it doesn't really matter, spam flags are a bit special, a single one is powerless but a few of them have super awesome powers. If it's spam, use the spam flag, it's essentially the same as writing "this is spam, purge this sucker" in a custom flag.
    – yannis
    Apr 12 '12 at 8:47
  • This isn't helpful if the spam is a comment, not an answer. There's no way to flag a comment as spam that I see. (In stackoverflow.com/questions/10937358/…, the spam was first posted as answer that was flagged and deleted. Then the same thing showed up as a comment.) Jun 7 '12 at 18:53

Not the answer you're looking for? Browse other questions tagged .