As Oded says, the Meta moderators consist of SE employees, which can be found here (not all will be mods, a lot of them are).

You can walk through the list, and check on the accounts tab. If you find a diamond ♦ after the Meta Stack Exchange site name, he or she is a mod here (at least they have that privileges).

This SEDE query has most of the SE employees / mods. There are some false positives though, so it needs some work. It will get you started:

select *
from   users
where  aboutme like '%Valued Associate%'
or     aboutme like '%Stack Exchange%'
or     websiteurl like '%//stackexchange.com'
or     websiteurl like '%//stackexchange.com/'

As Oded says, the Meta moderators consist of SE employees, which can be found here (not all will be mods, a lot of them are).

You can walk through the list, and check on the accounts tab. If you find a diamond ♦ after the Meta Stack Exchange site name, he or she is a mod here (at least they have that privileges).

This SEDE query has most of the SE employees / mods. There are some false positives though, so it needs some work. It will get you started:

select *
from   users
where  aboutme like '%Valued Associate%'
or     aboutme like '%Stack Exchange%'
or     websiteurl like '%//stackexchange.com'
or     websiteurl like '%//stackexchange.com/'

As Oded says, the Meta moderators consist of SE employees, which can be found here (not all will be mods, a lot of them are).

You can walk through the list, and check on the accounts tab. If you find a diamond ♦ after the Meta Stack Exchange site name, he or she is a mod here (at least they have that privileges).

As Oded says, the Meta moderators consist of SE employees, which can be found here (not all will be mods, a lot of them are).

You can walk through the list, and check on the accounts tab. If you find a diamond ♦ after the Meta Stack Exchange site name, he or she is a mod here (at least they have that privileges).

This SEDE query has most of the SE employees / mods. There are some false positives though, so it needs some work. It will get you started:

select *
from   users
where  aboutme like '%Valued Associate%'
or     aboutme like '%Stack Exchange%'
or     websiteurl like '%//stackexchange.com'
or     websiteurl like '%//stackexchange.com/'